# Line slope calculator x-5y=-22

**Straight line given by points A[3; 5] and B[8; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+4.4

**Canonical form of the line equation:**x-5y+22 = 0

**Parametric form of the line equation:**

x = 5t+3

y = t+5 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -22

**Y intercept:**y

_{0}= q = 4.4

**Distance line from the origin:**d

_{0}= 4.3146

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[5.5; 5.5]

**Perpendicular Bisector equation:**5x+y-33 = 0

**Vector OA = (3; 5) ; |OA| = 5.831**

**Vector OB = (8; 6) ; |OB| = 10**

**Scalar product OA .OB = 54**

**Angle ∠ AOB = 22°9'59″ = 0.3869 rad**